The magnitude and location of the resultant of the given load will be determined by integration.

4.6 Distributed Loads on Beams Example 6, page 1 of 3 A B w = w o sin w x L 6.

Determine the horizontal and vertical components of reaction at pin C and the force in the pawl of the winch in Prob. Distributed load diagram. Determine the reactions at the supports. 5–10. Determine The Reactions At The Supports. Qu. 669” is broken down into a number of easy to follow steps, and 30 words. Determine the normal reactions at the points of contact at A, B, and C of the bar in Prob. Determine the reactions at the supports A and B for the jib crane shown below.

5–18. 5-11. The sum of the moments about A is M A D 3 100 C 900 7 400 C 11F B D 0. (b) The sum of the forces: F X D 0, and F Y D F A C F B C 100 400 D 0.

Question: 5-11. The free body diagram is shown.

Neglect the weight of the members of the jib crane. The stone has a center of mass at G. Neglect the weight of the arm. 5.22 The uniform door has a weight of 100 1b and a center of gavity at G. Determine the reactions at the hinges if … determine the reactions at the supports

From which F B D 2200 11 D 200 N 5 Solutions 44918 1/23/09 5:11 PM Page 328 The answer to “Determine the reactions at supports A and B. 6 ft 500 lb/ ft 6 ft 8 ft 9 ft 700 lb/ ft 6 ft A C D B Prob.

(b) Determine the reactions at the supports. 100 N 400 N A B 900 N-m 3 m 4 m 3 m 4 m Solution: (a) Both supports are roller supports. See the answer. 400 N/m 3 M Prob. Since the solution to 6-69 from 6 chapter was answered, more than 348 students have viewed the full step-by-step answer. Also identify if the cable BC is in compression (C) or tension (T).

2 Determine the reactions at the supports 400 N/m Al 3 m 3 m B,=450N By-600N A=750N Get more help from Chegg Get 1:1 help now from expert Mechanical Engineering tutors This problem has been solved! A w x B x L dA = w dx The resultant force R = dA = w dx R = w o sin dx = w o [ cos ] = 1 2 A L 0 0 L

— 14 in. 0.8 in. Determine these forces and the force FB that the biceps B on the radius for equilibrium. 5–9.